Zerojudge e286

Zerojudge e286

題敘

https://zerojudge.tw/ShowProblem?problemid=e286
給兩場比賽中四局的兩隊比數,求輸贏與比分

想法

跟著題目照做即可

Code

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//By Koios1143
#include<bits/stdc++.h>
#define LL long long
#define IOS ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
#define pii pair<int,int>
using namespace std;
int tmp,A_win=0,B_win=0,tot_a=0,tot_b=0;;
int main(){
IOS
for(int k=0 ; k<2 ; k++){
tot_a = tot_b = 0;
for(int i=0 ; i<4 ; i++){
cin>>tmp;
tot_a+=tmp;
}
for(int j=0 ; j<4 ; j++){
cin>>tmp;
tot_b+=tmp;
}
cout<<tot_a<<":"<<tot_b<<"\n";
if(tot_a>tot_b)
A_win++;
else if(tot_a<tot_b)
B_win++;
}
if(A_win>B_win)
cout<<"Win\n";
else if(B_win>A_win)
cout<<"Lose\n";
else
cout<<"Tie\n";
return 0;
}

複雜度

$O(1)$